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2x^2+77x=0
a = 2; b = 77; c = 0;
Δ = b2-4ac
Δ = 772-4·2·0
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(77)-77}{2*2}=\frac{-154}{4} =-38+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(77)+77}{2*2}=\frac{0}{4} =0 $
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